Physics Help!!!!????

Question

I really need your help!

A space ship is observed traveling in the positive "x" direction with a speed of 150 m/s when it begins accelerating at a constant rate. The spaceship is observed 25 s later traveling with an instantaneous velocity of 1500 m/s at an angle of 55° above the +x axis.

What is the magnitude of the acceleration of the spaceship during the 25 seconds?

A). 1.5 m/s/s

B) 7.3 m/s/s

C) 28 m/s/s

D) 48 m/s/s

E) 57 m/s/s

What was the magnitude of the displacement of the spaceship during the 25 seconds?

A) 2.0 * 10^4

B) 1.4 * 10^4

C) 2.8 * 10^4

D) 1.0 * 10^4

E) 1.7 * 10^4

If you could please answer at least one of those. thank you

Answer 1

1st problem answer is A)

2nd problem answer is B)

Answer 2

Resolve the final velocity into x and y components

Vx = 1500 cos(55) = 860.365 m/s

Vy = 1500 sin(55) = 1228.73 m/s

Just use v = u + a*t on each component:

860.365 = 150 + 25 * Ax

Ax = 28.415 m/s^2

1228.73 = 0 + 25 * Ay

Ay = 49.15 m/s^2

Total acceleration is just the vector addition of Ax and Ay

A = sqrt(28.415^2 + 49.15^2) = 56.78 m/s^2

The second part is just the same game using v^2 = u^2 + 2as

to work out the displacement s in x and y and then Pythagoras.

Vx^2 = 150^2 + 2 * Ax * Sx

860.365^2 = 150^2 + 2 * 28.415 * Sx

Sx = 12629 m

Vy^2 = 0 + 2 * Ay * Sy

1228.73^2 = 0 + 2 * 49.15 * Sy

Sy = 15359 m

s = sqrt( 12629^2 + 15359^2) = 19884 m