Question:

Physics - Horizontal Kinematics question?!?

by Guest63043  |  earlier

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A Cessna 150 aircraft has a lift-off speed of

approximately 125 km/h.

What minimum constant acceleration does

this require if the aircraft is to be airborne

after a take-off run of 131 m? Answer in units

of m/s2.

What is the corresponding take-off time? An-

swer in units of s.

If the aircraft continues to accelerate at this

rate, what speed will it reach 24.8 s after it

begins to roll? Answer in units of m/s.

I got the answers to the first two parts correct but I cannot figure out the third one! Please show me how you've worked it out! :) Thanks.

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1 ANSWERS


  1. Let:

    u be initial speed,

    v be final speed,

    a be acceleration,

    t be time,

    s be distance.

    125 km/hr = 125 * 10^3 / 3600 = 34.7222 m/s.

    v^2 = u^2 + 2as

    a = (v^2 - u^2) / (2s)

    = (34.7222^2 - 0) / (2 * 131)

    = 4.60 m/s^2.

    s = t(u + v) / 2

    t = 2s / (u + v)

    = 2 * 131 / (0 + 34.7222)

    = 7.55 s.

    v = u + at

    = 0 + 4.60 * 24.8

    = 114 m/s.

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