Physics ~~ How to find speed of a collision given mass, degrees and initial speed?

Question

A puck of mass 0.50 kg approaches a second, identical puck that is stationary on frictionless ice. The initial speed of the moving puck is 6.0 m/s. After the collision, one puck leaves with a speed v1 at 30° to the original line of motion. The second puck leaves with speed v2 at 60°.

Photo to go with problem: http://i284.photobucket.com/albums/ll28/bathtub2008/08-56.gif

(a) Calculate v1 and v2.

____v1 = m/s

____v2 = m/s

Answer 1

Conservation of momentum:

p1i + p2i = p1f + p2f

Where p is momentum

the 1's, 2's, i's and f's are subscripts for 1st puck, 2nd puck, initial, and final.

And p = mv

If the puck was moving to the right along the x axis,

p1i + p2i = p1f + p2f

the equation can separate into x and y components, so the equation becomes a system of equations:

(m1) v1i + 0 = m1 v1f (cos 30) + m2 v2f (cos 60)

0 + 0 = m1 v1f (sin 30) + m2 v2f (sin 60)

OK, I've done the physics.

You do the math.