Physics Problem - Find Mass of Meter Stick?

Question

A meter stick balances at the 35.0cm mark whena 100g mass is hanging from the 20.0cm mark. What is the mass of the meter stick?

I first figured out the Torque Clockwise by going

50 - 35 = 15cm

Then I figured out the Torque Counter Clockwise by going

35cm - 20cm = 15cm

Tcw = (100g)(9.8m/s2)(15cm) = Tccw (Mms)(9.8m/s2)(15cm)

I got that the Mass of the Meter Stick (Mms) = 100g

Did I do this correct?

Answer 1

The three torqueing components are caused by:

1) 100 g acting ccw 15 cm from the fulcrum

2) .35Mms acting ccw 17.5 cm from the fulcrum

3) .65Mms acting cw 32.5 cm from the fulcrum

Try balancing those.

Hope this helps.