Physics Problem Involving Work?

Question

A 2500 kg elevator accelerates upward at 1.40 m/s^2 for 13.0 m, starting from rest.

1) How much work does gravity do on the elevator?

2) How much work does the tension in the elevator cable do on the elevator?

3) Use the work-kinetic energy theorem to find the kinetic energy of the elevator as it reaches 13.0 m.

4) What is the speed of the elevator as it reaches 13.0 m?

**Any help with this problem would be greatly appreciated.**

Answer 1

Gravity Work (W=MG)  2500*10= 25000

Tension in cable is = load = 2500 kg

K.E = 1/2mv^2 = 45500

Speed at 13m  (2aS = Vf^2 -Vi^) = 6 m /sec

Answer 2

1) 2500 x 1.4=  Y

Y   x  13meter=  answer.