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Physics Question about Velocity, Displacement, etc.?

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A car starts from rest and is given a constant acceleration of 10m/s2 for a total time of 5 seconds.

a.) Find the velocity at the end of 5 seconds?

b.) How far does it go during the first second?

c.) What is the displacement after 5 seconds?

Note: With Formula plss.Thanks.

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3 ANSWERS


  1. (a) v = at = 10(5) = 50 m/s

    (b) s = (1/2)at^2 = (1/2)(10)(1^2) = 5 meters

    (c) s= (1/2)at^2 = (1/2)(10)(5^2) = 125 meters


  2. 10m/sec*2 for 5 seconds.

    This mean that the car travels at 10 metres per second every second.

    First second -- 10 m

    2nd        "          20 m(It accelerates 10 m more in the second second, and the third, etc.)

    3rd         "          30 m

    4th          "          40 m

    5th          "          50 m

    After 5 seconds it will have travelled 150 metres, the sum of the seconds' acceleration.

    Calculus has the answer for you by formula:

                              10 m/sec*2 for 5 secs

                           = 5 x 2 x 10 m/sec

                           = 100 m /sec.

    My results are not eaual. You can crrect something for me.

    You'll get to know how to do the subject by this correction. Good on you.

  3. Formula; V2=V1+at  

    the newtons first eqn of motion

    put values for answer

    V2=final velocity

    V1=initial velocity

    a=acceleration

    t=time duration

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