Physics Tension Question?

Question

A 1400kg. steel beam is supported by two ropes

at angles rope 1.) 20 deg & rope 2.) 30 deg.

1.) What is the tension in rope 1?

2) What is the tension in rope 2?

Answer 1

W = 1400*9.806 = 13728

If 20 and 30 degrees above horizontal, then...

0 = T1 * sin(20) + T2 * sin(30) - 13728

0 = -T1 * cos(20) + T2 * cos(30)

T1 = 15,520 N to left, 20 degrees above horizontal

T2 = 16,840 N to right, 30 degrees above horizontal

CHECK

15,520*sin(20) + 16,840*sin(30) = 5,308 + 8,420 = 13,728

-15,520*cos(20) + 16,840*cos(30) = -14,840 + 14,840 = 0

If 20 and 30 degrees below vertical, then...

0 = T1 * cos(20) + T2 * cos(30) - 13728

0 = -T1 * sin(20) + T2 * sin(30)

T1 = 8,961 N to left, 20 degrees below vertical

T2 = 6,129 N to right, 30 degrees below vertical

CHECK

8,961*cos(20) + 6,129*cos(30) = 13,728

-8,961*sin(20) + 6,129*sin(30) = -3,065 + 3,065 = 0

Answer 2

is the beam horizontal or vertical or angled? You have to be more specific man...

Answer 3

T1y+T2y-W=0

T1sin20=13720N-T2sin30

T1=(13720N-T2sin30)/sin20

T2x=T1x

T2cos30=T1cos20

T2cos30=[(13720N-T2sin30)/sin20]cos20

T2=16192.68N

T2cos30=T1cos20

T1=(T2cos30)/cos20

**substitute value of T2

T1=14923.26N

T2=16192.68 newtons, 20 deg

T1=14923.26 newtons, 30 deg