Physics - acceleration ?

Question

An egg drops from a second-story window, taking 1.08 s to fall and reaching a speed of 10.6 m/s just before hitting the ground. On contact with the ground, the egg stops completely in 0.135 s. Calculate the average magnitudes of its acceleration while falling and while stopping.

= m/s2 (acceleration while falling)

= m/s2 (deceleration while stopping)

Please explain in detail i don't have my book yet. Would like more then answer. Thanks!

Answer 1

a=dv/t

acceleration = change in velocity/time

change in velocity=dv=10.6 m/s

while falling or stopping

"Calculate the average magnitudes"

In 1.08 seconds the egg falls

(acceleration while falling)

a = dv/t=10.6/1.08 = 9.81 m/s^2 "gravity"

In 0.135 seconds the egg stops

(deceleration while stopping)

a=dv/t=10.6/0.135 = 78.52 m/s^2