Physics? ball thrown upward vertically, maximum height?

Question

a ball is thrown upward with an initial velocity of 20 m/s. What maximum height does the ball reach?

Answer 1

Since you want to find the maximum height it reaches, the highest point of any object when thrown upwards has a final velocity of 0m/s because all the kinetic energy in the object is used to overcome the gravitational potential energy in it.

Since the ball is travelling upwards, the acceleration due to gravity has a negative value. Because this quantity is a vector, and as the ball goes up, it is moving in a direction opposite the acceleration due to gravity.

v^2=u^2 + 2as

0^2 = 20^2 +2(-10)s

400-20s= 0

-20s=-400

s=20m

The values substituted are all according to their SI units. Before solving the qn, check that all are in the appropriate units or else your results might be inaccurate.

The above equation is one of few you need to know to get the answer.

The s stands for displacement.

The u is initial velocity

The v is final velocity  

Answer 2

You'll need to define the ball size and weight to solve.

There are a number of physics issues going on here, not the least of which are gravity and air resistance.

Answer 3

ignoring air resistance

at its maximum height its velocity = 0

using

v^2=u^2+2as

(v final velocity - in this case 0 and u initial velocity)

0=20^2 - 2*9.8*s  (acceleration negative as acting downwards)

s = 20.4 m

Answer 4

intial velocity(u)=20m/s

final velocity(v)=om/s [as at max height no vel].

acceleration=9.8

using formula:  v^2=u^2+2as

bring u^2 and 2a to the left hand side as u have to find 's'.it becomes-

v^2-u^2/2*9.8=s

u get 20.4m/s

Answer 5

You can't figure out that question with only velocity. Wouldn't the initial velocity be 0?, because you are THROWING it, it started with no velocity. I don't know, maybe i'm wrong.