Physics ch9 ex4 question

Question

A 40 g ball of clay is thrown horizontally at 30 m/s toward a 2.0 kg block sitting at rest on a frictionless hi surface. The clayts and sticks to the block.

1)What is the speed of the block and clay right after the collision?

2)What impulse does the clay exert on the block?

3)What impulse does the block exert on the clay?

Answer 1

1.

Let u be the speed.

Equating momentum before and after collision:

0.040 * 30 = (2.0 + 0.040)u

u = 0.588 m/s.

2.

2.0 * 0.588 = 1.18 kg m/s.

3.

0.040 * 30 - 0.040 * 0.588

= 1.18 kg m/s.