Physics help (finding the voltage drop across a circuit) pic included?

Question

http://i328.photobucket.com/albums/l341/CristyAustin/Scan0004-1.gif

I dont know where to start...

Answer 1

The voltage across capacitors in parallel is the same, meaning the voltage drop across C2 and C3 is 241V.

The capacitance of the parallel pair needs to be determined, however, and is as simple to calcuate as adding the two capacitances.

Ceq = C2 + C3 = 6pf + 9pf = 15pf

Using the idea of a voltage divider circuit...

Ceq/C1 = Veq/V1

15/3 = 241/V1

V1 = 241/5 = 48.2

Total Voltage = 48.2 + 241 = 289.2 volts