Physics help!? like math wise?

Question

3Z-2H=X/(Y^2-2)

solve for Y.

This next one, the numbers are sub numbers.

M1C1(Tf-T1)=M2C2(Tf-T2)

solve for Tf

0 is sub zero

X=X0+V0t+(at^2)/2

solve for a

Answer 1

Y^2-2=X/(3Z-2H)

Y=sqrt( X/(3Z-2H) - 2)

Tf= ( M2C2(Tf-T2) ) / (M1C1)

(2/t^2) * ( X-X0-V0t ) =a

Answer 2

1.) 3Z-2H=X/(Y²-2)

Y² - 2 = X/(3Z-2H)

Y = √(X/(3Z-2H) +2)

2.) M1C1 (Tf - T1) = M2C2 (Tf - T2)

To simplify typing this, let:

a = M1C1

b = M2C2

a (Tf -T1) = b (Tf -T2)

aTf - aT1 = bTf - bT2

aTf - bTf = aT1 - bT2

Tf (a -b) = aT1 - bT2

Tf = (aT1 - bT2)/(a -b)

3.) X = X0 + V0t + ½at²

X - X0 - V0t = ½at²

2(X - X0 - V0t) = at²

2(X - X0 - V0t)/t² = a