Physics help never done it very simple i think?

Question

A car started from rest and accelerated at 3.28 metres per second squared (m.s^-2) . How far had the car travelled after 16.50 seconds?

Hi, ive never studied physics can someone please explain to me this.

Give your answer in metres (m) and round it to no (0) decimal places, using the normal convention.

Distance (m) =

Answer 1

s=ut+1/2atsquare

  =0*16.50+1/2*10*16.50square

  = 0+5*16.50

  = 82.5m

s=distance

u=initial velocity

t=time

a=accelaration

thats it

Answer 2

okay... is the car accelerating constantly at 3.28 m/s^2?  If it is, then you use the kinematic equation..

Distance= V_initial*time+1/2*acceleration*time^2

D=Vo*t+1/2a*t^2

And your problem doesn't involve an initial velocity.. so there is no Vo.

And, the reason this equation exists, just in case you are wondering  is through Calculus..

You take the Integral of V=Vo+a*t with respect to time and get

D=Vo*t+1/2*a*t^2

This is all assuming there is no friction, and the acceleration is constant.

Answer 3

its all good and easy man...

God bless Isaac Newton..

use his equation of motion.... u should know his equations of motion better than your name man...

here :    

                    distance = u*t + 0.5*a*(t^2)

                                      u= initial velocity

                                      t= time

                                      a= acceleration

(take initial velocity to be zero since the car starts from rest)

Thats all man.... easy ??

Answer 4

Well physics is simple as long as you keep the calculus and derivation of formulas out of the context. In this case it is very easy to solve. With no initial velocity, all you need is the formula:

v=1/2*a*Δt^2

where 'v' is final velocity, 'a' is acceleration and 'Δt^2' is called delta t, the change in time - in your case is 16.5 as well.

so:

v=1/2 * 16.5 seconds * 3.28 m/s^2 ≈ 27 meters

It may help to think of units. Look at the desired answer of meters and what you are working with - meters over time squared and time. If you square your time given and multiply it by acceleration, the times cancel and you are left with your desired unit. The 1/2 I won't go into why it's there, just trust the formula and s***w the calc.

-P