Physics help please!!?

Question

try as i might, i cannot figure out how to solve this problem.. my answer was 1/3 of the answer to this problem.

A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.0 m/s. The car is a distance [d] away. The bear is 26 m behind the tourist and running at 6.0 m/s. The tourist reaches the car safely. What is the maximum possible value for [d]?

Answer 1

if , the time taken for the tourist to run= the time taken by the bear to run after the tourist = t seconds

Tourist = T; The bear = B; Car = C

http://good-times.webshots.com/photo/252...

Answer 2

for the bear to catch the person, the bear must run a distance of d+26 meters in at least the time the person runs d meters.

dist=speed x time means that time=dist/speed

time for bear = (26+d)/6

time for person = d/4

these are equal when:

(26+d)/6=d/4 or when

4(26+d)=6d

104+4d=6d

104=2d or d=52 meters

Answer 3

(26 + d) / 6 for the bear = d / 4 for the tourist.  d resolves to 52.  Technically, the answer is that the distance is less than 52.  (52 is the exact distance when both the tourist and the bear would arrive at the car.  If I were the tourist, I'd want that distance to be a little bit closer. :-)

Answer 4

haha Idk Im not there yet in math lucky guess would be d=52 but thats toooooooo far! sorry but good luck it doesnt seem to hard