Physics help pretty basic? never done before?

Question

Hi can someone help me with this question i need to do;

In a rather silly physics demonstration, a watermelon was accidentally dropped from a bench, 111 centimetres (cm) above the floor. Calculate the impact velocity of the watermelon.

Remember: Always use 9.80 m.s-2 for the gravitational acceleration.

Give your answer in metres per second (m/s) and round it to three (3) significant figures.

Impact Velocity (m/s) =

Answer 1

okay, first convert your length units into metres

111 cm = 1.11m

now we have the initial velocity u = 0 m/s

using the equation of motion v^2 = u^2 + 2as

in slightly simpler and easier to remember terms,

v = root(2gh)

where:

v = final velocity,

g = a = acceleration

h = s = height

we have v = root(2 x 9.8 x 1.11) = 4.66 m/s

this seems like a reasonable answer.

Answer 2

U Can use the formula

v^2=u^2+2as

v^2= 0^2+2*9.80*111

      = 2175.6

root v^2= root 2175.6

v= 47m/s or 4.7 m/s