Physics-projectiles help needed calculate initial speed?

Question

can somone help me with this i have no idea.

A projectile was fired 2519 metres across level ground at an initial angle of 63.00 degrees above the horizontal. What was the initial speed of this projectile?

Give your answer in metres per second (m/s) and round it to the nearest metre per second.

Initial Speed (m.s-1) =

Answer 1

horizontal range (H) = 2519 m

Theta = 63.00 degrees

g = 9.8 m/s²

let the initial velocity be u

We have

H = (u² . Sin 2Θ) / g

=> 2519 = u² . Sin (2 * 63) / 9.8

=> 2519 = u² . 0.809 / 9.8

=> 2519 = u² . 0.08255

=> 2519 / 0.08255 = u²

=> 30514.83 = u²

=> u = 174.68

or u = 175 meters/sec

Answer 2

NO!