Physics question about displacement. ?

Question

Cars A and B start at rest. They both accelerate at the same rate. However, car A accelerates for twice the time as car B. Compare the displacement of car A to car B.

Answer 1

im sure this is in the right direction, and can help you out but im not sure about the answer

you can use the formula:

D=(initial)V*t + 1/2(a)t^2

for the first car it would be

D= 0 + (1/2)(1)(1)^2

D= .5

for the second car it would be

D= 0 + (1/2)(1)(2)^2

D= 2

so, i think, it would be 2 - .5 = 1.5 (whatever units you have) apart

again, not sure about the answer, but this is a step int he right direction.

Answer 2

When starting from rest, the displacement is given by:

d = ½at²

This means the displacement is in proportion to the SQUARE of the time.

(Hint: how much is 2²?)

Answer 3

it is also twice the acceleration

Answer 4

A=2m/s^2,B=1m/s^2  S=?in both

  V^2=U^2+2as  write two of this formular an compare

  note since u=0,an v=unknown I can neglet it

2as=2as   (as)A=(as)B   2*s=1*s   sA an sB IS 2 ratio 1 in metres