Question:

Physics question about superpositions?

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Fringes of separation y are observed in a plane 1 m from a Young’s slit arrangement illuminated by yellow light of wavelength 600 nm. At what distance from the slits would fringes of the same separation y be observed when using blue light of wavelength 400 nm?

Is the answer 0.67 meter?

I think I know how to do it, but I'm just not sure...

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  1. ∆x = λD/a

    where D = 1m, a = distance between the 2 slits, λ = wavelength of light

    Making it useful for this question,

    a∆x / λ = D

    since y and a remain constant,

    D = k / λ where k is a constant (= a∆x)

    D₁/ D₂= λ₂/ λ₁

    where D₁is when yellow light is used, D₂is when blue light is used.

    D₂= 0.67m

    Hope this helped=)

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