Physics question involving distance/displacement.?

Question

a race car on a flat level road accelerates at 10m/s/s from 100m, before driving off a 30m cliff.

1. where does the car land?

2. how fast is the card going before it lands?

3. if the landing takes .01 secs, how many g's does the driver experience?

please help me out and walk me through this; ive been thinking about this problem for a while.

thanks!

Answer 1

Vx = √(2ax) = √(2*10*100) = 44.72 m/s

Vy = √(2gy) = √(2*9.8*30) = 24.248 m/s

t = √(2y/g) = √(2*30/9.8) = 2.474 sec

1) D = Vx*t = 44.72*2.474 = 110.653 m from the base of the cliff.

2) Vf = √(Vx²+Vy²) = 50.87 m/s

3)  av = dV/dt = Vy/.01 = 2424.8 m/s² = 247.4 g.