Question:

Physics question on amps and ohms?

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In an electric circuit, voltage is equal to the product of current and resistance. A radio hobbyist measures a current of 1.2 amps when a 20-ohm resistor is connected in a circuit with a battery of unknown voltage. When the first resistor is replaced with an unlabeled resistor, the current in the circuit is 2 amps. What is the value of the unlabeled resistor?

12 ohms is right, but I got 33.3 ohms.

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  1. I got to 12 by looking at the ratio of change in the amps.  You went from 1.2 to 2, which is a change of 0.6.  

    Ohms went from 20 to ?.  Multiply 20 by 0.6 and you get 12.


  2. Using Ohm's Law,

    V = IR

    where

    V = voltage

    I = current

    R = resistance

    First step,

    V = 1.2 * 20 = 24 volts

    This is the circuit's voltage and with a current of 2 amp with an unknown resistor,

    24 = 2R

    and solving for R,

    R = 24/2

    R = 12 ohms

    Hope this helps.

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