Physics question problem

Question

Two horizontal forces act on a 2.0kg chopping block that can slide over a frictionless kitchen counter, which lies in an xy axis plane. One force vector F1=(-3.0)N i (4.0N) j. FInd the accelration of the chopping block in unit vector notation when the other force is (a) vector F2 (-3.0N)i (-4.0N)j. (b) vector F2=(-3.0N)i (4.0N)j. (c) and vector F2=(3.0N)i (-4.0N)j.

Please explain

Answer 1

m = 2.0kg

mu (friction) = 0

add F1+F2 to get the vector sum of forces. recall F=ma to get acceleration.

a) acceleration is just going to be in the i (or x) direction F=(-6.0N)i=ma ... divide by mass, to get acceleration is -3.0m/s^2

b) F1+F2 = -6,8  N  (in i,j respectively) ... so a = -3,4 m/s^2

c) acceleration is 0 since F1+F2 =0