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Pleas i need your help- algebra?

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1.the sum of 3 consecutive integers =279 find the integers?

2.the sum of 2 con. odd integers is 112find integers?

3.find 3 con. odd integers such their sum is decrased by the seconds equals 50. Thanks! and would someone please explain? answer as many as you can.

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  1.   279 divided by 3 is 93    so you take one less which is 92 then one more 94 and you get the answer     92+93+94=279

    112 divided by two is 56 so you take the odd number before it which is 55 (which is one less than 56) and the odd number after it 57 (which is one more) and you have 55+57=112

    I'll work on the 3rd


  2. i forgot how to do those

  3. 1.  92 93 94

  4. 1. 92,93,94. in oder to get 279 the last 3 digits of the con. integers must equal 9. 2,3,4 equals 9. so we have the last numbers. since the are con we can assume that all the tens are in the same bracket, there fore 27 divided by 3 is 9, there fore the numbers are in their nineties therefore the numbers 92,93,94

    i cant do the rest. its been years since i was at school

  5. 1. 92+93+94=279

    2. 55+57=112 (two consecutive odd integers)

    3. 23+25+27=75, 75-25= 50

    consecutive means one after another if you didn't know.

        hope this helped! :)

  6. 1. x + (x + 1) + (x + 2) = 279.  Take x as the first integer, and the following 2 integers would be x + 1 and x + 2.

    2. x + (x + 2) = 112.  Same thing, but assumes x is odd and x + 2 is the next odd integer.

    3.  I don't understand the question.  


  7. 1. 92,93,94

    the equation is x+x+1+x+2=279

    3x+3=279

        -3=-3

    3x=276

    /3=/3

    x=92

    so if x=92 then x+1=93 & x+2=94

    2. again x+x+2=112 since they are odd integers they will increase by 2

    2x+2=112

        -2= -2

    2x=110

    /2= /2

    x=55 and if x=55 then x+2 is 57

    3. I dont understand what seconds is that power or how many seconds need more info i think. if not then i really just dont understand that one sorry

  8. 1. 92, 93, 94

    2. 55, 57

    3. sorry i dont understand this one

  9. Why don't you ask you teacher or your parents. I'm only in 6th grade


  10. x+1=y

    y+1=z

    x+y+z=279

    x + (x+1) + (x+2)=279

    3x+3=279

    3x=276

    x=92

    y=93

    z=94

    use the same logic

  11. 1.  x + (x+1)+ (x + 2) gives you the sum of  three consecutive integers. Now Just solve the equation:  

    x + (x+1)+ (x + 2) = 279

    3x = 3 = 279

    3x = 276

    x = 92

    Therefore the three integers are 92, 93, and 94

    2.  Use the same idea for this one, but since only odd numbers are applicable, use x + (x+2) = 112

    2x + 2 = 112

    2x = 112 - 2

    2x = 110

    x = 55, so the numbers are 55 and 57 (which do add to 112)

    3.  Same general procedure

    [x + (x+2) + (x + 4)] -(x+2) = 50

    3x + 6  -x -2 = 50

    2x + 4 = 50

    2x = 46

    x = 23

    23 + 25 + 27 -25 = 50

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