Please, I need help with this...?

Question

...parallel to the line 2x-y=-2 and passes through point (0,0)

I started to work on it but I got stuck with the 0,0 point.

Answer 1

y=2x+2

The slope is 2, so the parrallel line also has a slope of 2,

and it passes through (0,0)

Use Point-Slope form

y-y1=m(x-x1)

y-0=2(x-0)

y=2x

Answer 2

First, we rewrite 2x - y = -2 in slope-intercept form:

y = 2x + 2

The slope is 2, so the equation of your line begins as

y = 2x + b.

This line must pass through the point ( 0, 0 ) so

0 = 0 + b

so b = 0 and the equation of your line is

y = 2x.

Answer 3

2x-y=-2 is the same as y= 2x+2

parallel line has the same slope so

y=2x+b is the new equation

plug in 0,0 to find b

0=2(0)+b

0=0+b

0=b

so the  equation is y=2x+0

Answer 4

Rearrange your equation y = 2x+2. If a line is parallel to this it has the same gradient (slope) which in this case is +2

Now use the general equation of the line y=mx+b. In this equation m=slope which we know is 2 so we have y=2x+b

Now put in your values (0,0) as we know this is a point on the curve and we find that 0 = 2*0 + b --? 0=0+b --> b=0

So the equation of your line is simply y=2x

Hope that helps!

Answer 5

the slope stays the same if its parallel.

so, you have to change the y intercept.

to do that, you need to put the equation in slope-intercept form:

2x-y=-2

-2x     -2x

-y=-2x-2

y=2x+2  

you change the 2 in to 0, because thats the y-intercept

y=2x+0

y=2x <answer