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Please Help!!! I can't solve this physics question?

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a pizza box thrown across the room strikes the floor with a horizontal velocity of 2.0m/s. if the 300-g box encounters a floor with a coefficient of kinetic friction of 0.3, how far will the box slide before coming to rest?

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  1. mass * deceleration = coeff-friction * mass * g

                                                                                      where g = 10

    Now you know the deceleration, find the distance:-

    velocity^2 = 2 * deceleration* distance


  2. W=mg=300/1000 X 9.8 =2.94 newtons

    counter force = 2.94 X 0.3 = 0.882 newtons

    1/2 mv ^2 = .882 x Distance so {.5x.300}2^2 =0.882 x Distance. 1=1.47 X distance. so distance = .68 meters =68cm.

  3. Depends on whether it has a pizza in it or not!

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