Please Help! Pre-Cal question?

Question

Ok i know this is a really easy question but the 0 at the end just confuses me :/

can you please explain how to do this

x^2+6x-3=0

THanks soo much :)

Answer 1

you could use the quadratic formula to solve and get two possible answers for x.

x= -3+2 root 3 or -3-2 root 3

Answer 2

the problem is telling you to solve for x when y=0

to do this you must factor

for ex. (x-2) to solve for x set this equal to zero  x-2=0 x=2

however you cannot  factor for your problem so you must use the quadratic formula

Answer 3

It's quadratic formula x = -b ± √ (b² - 4ac) all over 2a

Answer 4

100:)

easy ..:)

Answer 5

use the quadratic equation.

Answer 6

use the quadratic formula

Answer 7

it just means that you have to solve for x.

use quadratic equation.

a= 1   b = 6   c=-3

-b (plus or minus) square root of [b^2- 4ac] all divided by 2a.

so it would be -6 (+or -) squareroot of [6^2 -4(1)(-3) / 2(1)

-6 (+or -) square root of 48 /[all divided by 2]

so x=22 or 27