Please answer this... first one who answers this right will receive 10 pts.?

Question

1.) [(75-26)/7]+[4x(84/12)]

2.) 5(2+3+4)-[(25/5)+16-5]

3.) 15x4+(20/4)-(15x3)+32

4.) (7+15)/(19-8)-[2 to the power of 3(5-6)]

5.) {6to the power of 2+7[6-2(10/5)+3to the power2x2]}/4

please show you solutions....

and lastly..

2+(6-3)+9

i will surely give you points.....

Answer 1

1.) [(75-26)/7]+[4x(84/12)]

   = ( 49 / 7 ) + ( 4 x 7 )

   = 7 + 28

   = 35

2.) 5(2+3+4)-[(25/5)+16-5]

   = 5(9) - (5 + 11)

   = 56 - 16

   = 40

3.) 15x4+(20/4)-(15x3)+32

   = 20+5-45+32

   = 12

4.) (7+15)/(19-8)-[2 to the power of 3(5-6)]

  = 22/11 - 2^-3

1.875

and the last one i will get back 2 u

Answer 2

its 4 am.. you owe me.

1. 35

2. 29

3. 52

4. -4

5. Take too long to simplify..

(6 to the power of 72 + 3 to the power of 81) /4

Answer 3

1)    =49/7+4*7     =7+28=35)

2)5(9)-{(5)+11)}   =45-16=29

3)60+5-{(45)+(32)}  = 65-(77)=-12

4){(22)/(11)}-(2^-3)  =2-(-8)=10

5)6^{(9)*(8*2)}+3{3(-1)}  =6^(144)+3(2)=....

6)2+12=14

Answer 4

following BODMAS rule:

1.    21

2.    29

3.    22

4.    22/11 - 1/2(to the power 3)= 15/8

5.     669/4= 142.25

and lastly......

        14  

Answer 5

Follow the BODMAS rule for all these problems;

BODMAS - Brackets of Division Multiplication Addition Subtraction.

ie.....everything in the brackets comes first and then the rest and in the order of division first then multiplication then addition and then subtraction.

So;

1)

[(75-26) / 7) + (4*(84/12)]

= (49/7) + (4*7)

= 7 + 28

= 35

2)

5(2+3+4) - [(25/5) + 16 - 5]

= 5(9) - (5+16-5)

=45-16

=29

3)

15(4) + (20/4) - 15(3) + 32

= 60 + 5 - 5 + 32

= 92

4)

(7+15)/(19-8) - (2 ^ 3(5-6))

=(22/11)  -  (2 ^ -3)

= 2 - (1/2 ^ 3)

= 2 - 1/8

= 15 /8

= 1.875

5)

(6^2 + 7[6 - 2(10/5)] + 3^2 x 2) / 4

= (36 + 7[6 - 2(2)] + 9 x 2])/4

= (36 + 7[6 - 4] + 18])/4

= (36 + 18 + 7[2])/4

= (54 + 14)/4

= 68/4

= 17

and lastly;

2 + (6-3) + 9

= 11 + 3

= 14

Hope that helps !!!

Answer 6

Its just oder of operations, do inside the parenth and do multi/div next

1) (49)/7 + 4(7)

7+28

35

2) 5(9) - ((5)+16-5)

45 - 16

29

you can do the rest..just follow the rules

Answer 7

1)

[(75 - 26)/7] + [4 x (84/12)]

= 49/7 + 4 x 7

= 7 + 28

= 35

2)

5(2 + 3 + 4) - [(25/5) + 16 - 5]

= 5(9) - [5 + 11]

= 45 - 16

= 29

3)

15 x 4 + (20/4) - (15 x 3) + 32

= 60 + 5 - 45 + 32

= 65 - 45 + 32

= 20 + 32

= 52

4)

(7 + 15)/(19 - 8) - 2^3(5 - 6)

= 22/11 - 2^3(-1)

= 2 - (-8)

= 2 + 8

= 10

5)

{6^2 + 7[6 - 2(10/5)] + 3^2 x 2]}/4

= {36 + 7[6 - 2(2)] + 9 x 2]}/4

= {36 + 7[6 - 4] + 18]}/4

= {36 + 18 + 7[2]}/4

= {54 + 14}/4

= 68/4

= 17

6)

2 + (6 - 3) + 9

= 2 + 3 + 9

= 5 + 9

= 14

Answer 8

do your own homework!!

1> 35

2>29

3>52

4> -5

the last one is 15

Answer 9

Is this your maths homework???