Please check if this is the correct ionic equation.. 10 points?

Question

The equations are redox displacement reactions:

a) Bromine water is added to a solution of potassium iodide and the mixture is shaken.

MY ANS: Br (aq) + KI (aq) ---> KBr (aq) + I (s)

Br is reduced, I is oxidised. But is this correct - it is not ionic (ie. no K+ ions, Br- ions etc). But if I did it that way, pretty much all will cancel out!?!

b) Also, Magnesium is added to lead nitrate solution.

Mg(s) + Pb(NO3)2 ----> Mg(NO3)2 + Pb (s)

Thus, Mg(s) + Pb2+ (aq) ----> Mg2+ (aq) + Pb (s)

Mg is oxidised, Pb reduced.

Please check these! Thanks in advance, 10 points for best answer!

Answer 1

a) Bromine is Br2(aq) and Iodine in solution is I3-, or I2(aq).  Bromine will be reduced as iodine is oxidized to I2.  Potassium is indeed a spectator ion. The typical "molecular equaiton".

Br2(aq) + 2KI(aq) --> 2KBr(aq) + I2(aq)

or the ionic equation

Br2(aq) + 3I- --> Br- + I3-

b) magnesium will be oxidized as it reduces lead to the metallic form.

Mg(s) + Pb(NO3)2(aq) --> Mg(NO3)2 + Pb(s)

or the ionic equation, where nitrate ion is a spectator ion

Mg(s) + Pb2+ --> Mg2+ + Pb(s)