Please help math question?

Question

Can you show me the steps of how to solve this equation

1/5^x=5^2+x

thanks!

Answer 1

(1/5)^x = 5^(2+x)

( 5^(-1) )^x = 5^(2+x)

5^(-x) = 5^(2+x)

Therefore -x = 2 + x

2x = -2

x = -1

Hope that helps.

Answer 2

im stupid but help me

http://answers.yahoo.com/question/index;...

Answer 3

Assuming  1/5^x=5^(2+x)

                  5^(-x)=5^(2+x)

                       -x=2+x

                        2x=2

                          x=1

                        

Answer 4

okay so you have...

1/5^x but you know that when an exponent is negative... you put the base as a denominator...

so 1/5^x also equals 5^(-x)

So... 5^(-x) = 5^(2+x)

Since 5 is the base for either side of the equation (equal sign) you can automatically ignore them (according to logarithmic rules, which I hope you know)

so... 5^(-x) = 5^(2+x) also equals...

-x = 2+x  (see how we ignore the 5's? since they're both the same base?)

so... with simple rearranging we get

-2 = x+x = 2x

Therefore, isolating x, we get

x=(-1)

Answer 5

1/5^x = 5^(2 + x)

5^(- 1x) = 5^(2 + x)

- x = 2 + x

2x = - 2

x = - 1

Answer: x = - 1