Please help me last question-algebra?

Question

find 4 consecutive integers such thet the sum of the 2nd and 4th is 132

thanks to all answers!

Answer 1

There is probably a more elegant way to do this, but this approach works:

Since you are looking for consecutive numbers, you know that the 2nd and 4th number will be very close to 132 divided by 2.

132 / 2 = 66

I know that the 2nd number will be a little lower than 66, and the 4th will be a little higher, so I try a few in the ballpark, and come up with:

64,65,66,67

65+67 = 132

So your 4 integers are

64,65,66,67

Answer 2

64 65 66 67. 65+67=132

Answer 3

the answer is 64,65,66,67

I found the answer by

(x+1)+(x+3)=132 which would be the 2 and 4 numbers

2x+4=132

   -4= -4

2x=128

/2=/2

x=64  and if x=64 then x+1 is 65 and x+3 is 67 so now you know the 1,2,and 4, since they are cons then obviously the 3 is 66 sure there is a more correct way of doing it but this works as well