Please help me on this math question?

Question

in triangle ABC, AB = x, AC = 2x and BC = 4 square root of 5. Find the value of x

please help me!!!

i try to solve it but i couldnt get the answer

Answer 1

There seems to be some information missing.  Is one of these angles defined as a right angle?

x = 1 or x = 2 result in valid triangles.

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Edit

Assuming angle A is a right angle

x^2 + (2x)^2 = (4*sqrt(5))^2

x^2 + 4x^2 = 80

5x^2 = 80

x^2 = 16

x = 4

Assuming angle B is a right angle

x^2 + (4*sqrt(5))^2 = (2x)^2

x^2 + 80 =  4x^2

80 = 3x^2

80/3 = x^2

x = sqrt(80/3) = 4*sqrt(5/3)

Angle C can't be a right angle.  Angle C must be less than angle B, since AB is less than AC

Answer 2

This can only be solved if the triangle is a right triangle.

Hopefully, you meant to say right triangle.

x^2 + (2x)^2 = (4*sqrt 5)^2

x^2 + 4x^2 = 80

5x^2 = 80

x^2 = 16

x = 4