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Please help me on this physics problem?

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A car is traveling 25 m/s when the driver sees a child standing on the road. He takes 0.8 s to react, then steps on the brakes and slows at 7.0 m/s2. How far does the car go before it stops? please help. ive been struggling with this one all day long. first accurate answer gets 10 points!!! thanks!

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  1. You want to find stopping distance s given:

    initial speed u = 25 m/s,

    final speed v =  0,

    acceleration a = - 7.0 m/s^2.

    Using the equation v^2 = u^2 + 2as:

    0 = 25^2 + 2(- 7.0)s

    = 625 - 14s

    s = 625 / 14

    = 44.64 m.

    The total distance travelled is s plus the distance travelled before breaking starts. That is:

    25 * 0.8 = 20 m.

    Total stopping distance

    = 44.64 + 20

    = 64.6 m to 3sf.

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