Please help me solve this problem?

Question

a+6a-9=30.

Am in the seventh grade and this is my first time doing algebra

Answer 1

a+6a-9=30

       +9+9

a+6a=39

7a=39

divide each side by 7.

a= 5.57..

theres more numbers..round it off.

Answer 2

solve for the variable. Put the As together to get

7a-9=30 (7a+-9=30)

Since the 9 is negative, add nine to both sides of the equation. Adding nine to the left side neutralizes the -9, and then add it to the right to balance it out. Then you have

7a=39 Divide by 7 to get the a by itself and you have

a=5.5714 (5.6 for simplification)

Answer 3

6a's plus 1 a is 7a's

7a - 9 = 30

add 9 to both sides

7a - 9 + 9 = 30 + 9

now tidy up

7a = 39

now divide both sides by 7

a = 39/7

teacher may need to help you still

Answer 4

You want to separate the variables and the actual numbers.

a + 6a - 9 = 30

^ You can combine a and 6a, and that gives you...<insert answer here>

#a - 9 = 30

You need to separate the 9 from the a's. So you add 9 to both sides.

#a = 30 + 9

30 + 9 = ...<insert answer here>

Now you get the A by itself. So if you had 2x = 4, you'd divide by 2 to get the variable alone.

Kind of got an idea?