Please help me with this chemestry problem!!?

Question

If 150.0 grams of sodium phosphate react with 200.0 grams of iron (II) sulfate, how many grams of iron (II) phosphate will be formed and what is the limiting reactant?

Answer 1

I won't solve the entire problem (I've answered SO many questions like this one on Y!A) but I will give you the balanced equation and some hints

2Na3PO4 + 3FeSO4 ---> Fe3(PO4)2 + 3Na2SO4

First off, calculate the number of moles of each reactant

number of moles = mass / molar mass

Divide the molar mass of each reactant by its coefficient in the balanced equation. The smallest quotient will belong to the limiting reactant.

Good luck! =)