Please help on How to transform this function in standard form?

Question

How to transform this function in standard form? And what is the values of a,b, and c?

3x^2 y=(2x-1)(2x-1)

Thanks! for the help

Answer 1

3x^2+y=(2x-1)(2x-1)

3x^2+y=4x^2-1

y=x^2-1

The standard form of quadratic function is:

y=ax^2+bx+c, so, as your function is y=x^2-1 ==>

a=1, b=0 and c=-1