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Please help short chem question again???

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how many moles of ammonium ions are in 0.557 g of ammonium carbonate???

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  1. find moles of (NH4)2CO3 using its molar mass:

    0.557 g @ 96.09 g/mol g/mol = 1.946e-4 moles (NH4)2CO3

    1.946e-4 moles (NH4)2CO3 has twice as many moles of NH4+ ions

    Your answer is: 3.89e-4 moles of NH4+ ions

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