Please help with these 2 equations?

Question

2/7(4m-18)=12

And

-5/6(9+2x)=40

Trying to solve for m and x =] Thanks

Answer 1

1)  2/7(4m-18)=12

The 2/7 fraction needs to move to the other side, flipping the fraction in the process.

4m - 18 = 12 x 7/2 = 42

Move every term with the variable to the left and every term without the variable to the right, remembering to switch signs when you switch sides.

4m = 42 + 18 = 60

Divide to get m on its own.

m = 60 / 4 = 15

2) -5/6(9+2x)=40

The same process as above solves this one too.

9+2x = 40 x -6/5 = -48

2x = -48 - 9 = -57

x = -57 / 2 = -28.5

Answer 2

) 16d-(4-5d)=19

-Distribute negative: 16d - 4 + 5d=19

-Add: 21d - 4=19

-Add again: 21d=23

-D=23/21

2) 7(6x-1)+x=36

-Distribute: 42x - 7 + x=36

-Add: 43x - 7=36

-Add again: 43x=43

x=1

3) 2-sevenths(fraction)(4M-18)=12

-Put into numbers: 2/7(4m-18)=12

-Mutiply: 4m-18=42

-Add: 4m=60

m=15

4) 75=3(-10T-3)+6T

-Distribute: -30T - 9 + 6T=75

-Add: -24T - 9=75

-Add again: -24T=84

T=7/2

5) negative five fifths(fraction)(9+2x)=40

NOTE: isn't negative five fifths negative one?

-Put into numbers: -1(9 + 2x)=40

-Distribute: -9 - 2x=40

-Add: -2x=49

x=-49/2 or 24.5