Please o please help its to hard?

Question

a train leaves the station at 6:00 pm traveling west at 80 mi/h. on a parallel track, a second train leaves the station 3 hours later traveling west at 100 mi/h. at what time will the second train catch up with the first????

also:

a rectangular picture frame is to be 8 inches longer than it is wide. dennis uses 84 inches of oak to frame the picture. what is the width of the frame????

Answer 1

For the second problem the width of the frame is 17 in.

These are the steps to follow:

Let l = w+8

2l + 2w = 84 (formula for area)

2(w+8) + 2w = 84 (substitue l)

2w + 16 + 2w = 84 (Distribute)

4w = 84 - 16 (combine like terms)

4w = 68

w = 17

Answer 2

distance = speed x time

You want to know how much time will pass before the distance traveled by train A and train B are the same (If distance of A and distance of B are the same, then speed x time of A and speed x time of B will be the same).

80(t+3) = 100t

80t + 240 = 100t

240 = 20t

t = 12h (this is the time the second train will have traveled; the first train will travel for 3 more hours = 15 hours)

They will catch up at 9am the next morning.

A frame is basically a perimeter:

2(l+w) = 84

2(w+8 + w) = 84

2w + 16 + 2w = 84

4w = 68

width =17 inches

Answer 3

The first one > the 2nd train will reach the 1st train at 9AM the following day >  100 mph x12 hours = 1200 miles for train 2 .  For train 1 80 mph x 15 hours = 1200 miles.  Add 15 hrs to 6 PM, or 12 hrs to PM = 9 AM

PS > you should write >> It's too hard

Answer 4

t is the time the first train travels

t-3 is the time the second train travels

Both trains go the same distance and distance=speed*time

80t=100(t-3)

80t=100t-300

20t=300

t=15 hours

so 6:00 p.m. plus 15 hours is 9 a.m.

For the second question:

perimeter is 2*length + 2*width

the l=w+8 for this frame so:

84=2l+2w

84=2(w+8) +2w

84=2w+16+2w

84=4w+16

68=4w

w=17

and l is 17+8 or 25