Please solve by any method?

Question

9x=√81x-10/2

Answer 1

9x = √81x - 10/2

9x = √81x – 5

9x + 5 = √81x  ---------- squaring both sides

81x² + 90x + 25 = 81x

81x² + 171x + 25 = 0

a = 81, b = 171, c = 25

x = [– b ± √(b² – 4ac)] ÷ 2a

x = [– 171 ± √(171² – 8100)/162

x = [–171 ± 145.4]/162

x = – 0.15803 or x =  ÃƒÂ¢Ã‚€Â“ 1.9531

--------

Answer 2

9x=√81x-10/2

9x+10/2 = -√81x

9x+5 =  -√81x

square both sides

(9x+5)^2 = 81 x^2

81x^2+90x+25 = 81 x^2

90x=-25

x=-25/90

x= -5 /18

I have assumes it was sqrt(81x)

Answer 3

If this is 9x = squareroot(81)x - 10/2, then it can't be solved.  the square root of 81 is 9, so...

9x = 9x -10/2

subtract 9x from both sides and you get:

0 = 5

Are you missing parentheses somewhere?

Answer 4

9x=(√81x-10)/2

18x - √81x +10 =0

18x -9√x + 10 =0

let x= a^2, so √x = a

18a^2 -9a +10 =0

using quad formula

-b+- sq rt(b^2-4ac)  / 2a

a= (1+ - √71i) / 4

x = a^2 = [(1+ - √71i) / 4]^2

x = 1+√71i -71 / 16  or x = 1-√71i -71

x=( √71i - 70) / 16   or x=( -√71i - 70) / 16

Answer 5

Due to lack of brackets , this question may be read in MANY different ways.

BRACKETS ARE A MUST.