Pleaseplease help with physicss?? im confused..?

Question

1. At a certain location, the Earth's magnetic field has a magnitude of 5.6 10-5 T and points in a direction that is 72° below the horizontal. Find the magnitude of the magnetic flux through the top of a desk at this location that measures 110 cm by 66 cm.

__Wb

2. A uniform magnetic field of 0.0260 T points vertically upward. Find the magnitude of the magnetic flux through each of the five sides of the open-topped rectangular box shown in the figure, given that the dimensions of the box are L = 33.5 cm, W = 12.0 cm, and H = 10.0 cm.

__Wb (through either long side)

__Wb (through either short side)

__Wb (through bottom)

http://www.webassign.net/walker/23-26.gif

Answer 1

1)

Flux =ABcos(angle)

A = (1.1m)(0.66m) = 0.726 m^2

Bcos(72)=  (5.6 X10^-5 T )(cos72) =1.736 X 10^-5T

Flux = (0.726 m^2)(1.736 X 10^-5T) = 1.26 x 10^-5Wb

2)

the only Flux is throught the top and bottom. the flux through the sides is 0 because the angle is 0

The flux through the bottom is - and the flux throgh the top is + the same value

Flux (top) = ABcos(0)= AB=LWB

Flux bottom = LWcos(180) = -LWB

Answer 2

ohhhh... physicss, i thought you said psycics lmao