Pls help me solve this problem!!!!?

Question

the question is there is a 275 ft. of material to fence a pen w/ 3 rectangular sections next to each other & 1 side is the wall. Find the dimensions of the pen of largest area.

thanks

Answer 1

Cheer!

Answer 2

The largest area of any perimeter is a circle.  The next is a square.

So divide the 275 by three to make the three sides of a square. So 91.6666.  or 91 and 2/3 feet.   91 feet 8 inches would be the length of each fence.

Answer 3

sorry, idk!

Answer 4

the question is there is a 275 ft. of material to fence a pen w/ 3 rectangular sections next to each other & 1 side is the wall. Find the dimensions of the pen of largest area.

life rocks here it is

So I picture it as 3 rectangular section place side by side with one side the wall.

This means that they have the same Width and Length.

Given:

Length of the fence = 275 ft

Assumed the Length is twice the Width ← Eq 1

Peremeter = 2Width x  Length ← Eq 2 (note the other side is wall)

Peremeter = 2(Length/2) x  Length

Peremeter = (Length)²

Length = √ Peremeter

Length = √ 275

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Length = 16.58 ft

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from EQ 1

Length = 2 Width

Width = Length/2

Width = 16.58/2

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Width = 8.29 ft

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Dimension of Pin for Combine Area = Length  x  Width

Dimension of Pin for Combine Area = 16.58  x  8.29

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Ans:: Dimension of Pin for Combine Area = 137. 45 sq ft

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The Individual Area = Combine Area / 3

The Individual Area = 137.45 / 3

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Individual Area = 45.82 sq ft

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hope this helps

Answer 5

Need more information. What other size requirements?