Plz help me in this problem.i ud appreciate.

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Cn some1 plz help me in this problem.i wud appreciate?

the standard free energy change for the hydrolsis of ATP was given by ATP(aq) H2O=ADP(aq) Pi(aq)...........ΔGr... rxn=-30.5kj

In a particular cell,the concentration of ATP,ADP & Pi are 0.0031M,0.0014M & 0.0048M respectively.calculate the free energy change for the hydrolysis of ATP under these conditions(assume a temperature of 298K.

Answer 1

In response to your e-mail...

ATP(aq) + H2O(l) <--> ADP(aq) + Pi(aq)

We know that free energy is related by

ΔG = ΔGo(reaction) + RTlnQ, where

Q = equilibrium quotient = [products] / [reactants] = 0.0021677419

R = 0.008314 kJ K^(-1)mol(-1)

Plug and chug.

ΔG = ΔGo(reaction) + RTlnQ, where

ΔG = (-30.5kJ) + (0.008314)(298)ln(0.0021677419)

ΔG = -45.70 kJ

[Answer: see above]