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Poker question someone help (we have been having a big argument about it)?

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if player one has a 3 of a kind with all queens and player 2 has a 3 of a kind with all 10's and player ones high is queen and player twos high is ace who wins?

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  1. the face cards rule over everything except the ace so the three 10's with an ace kicker still loses because the kicker is ruled out by the 3 queens with a queen kicker ... and if i may ask how do you have 3 queens with an ace kicker isn't that a four of a kind?


  2. 3 queens wins because they are a higher three of a kind.

  3. PLAYER ONE WINS QUEENS BEAT THE TENS.

  4. Needless to say, everyone gave meaningless answers except the first guy, since they were all repeating.

    But seriously, you have been having a big argument about it?  You really shouldn't be playing poker if you don't know the rules.  And the rules are on the internet in dozens of places.

  5. Queens for sure. The high card would only matter if both hands were the same, which would be impossible with two three-of-a-kinds anyway.

  6. player one has a higher 3 of a kind.  

    you don't need the kicker.

  7. 3 queens beat 3 tens. doesn't matter what the other cards are

  8. Queens would still win. Ace high doesn't work in that situation unless you have a pair of them.


  9. THE QUEENS

  10. 3 Queens beats 3 Tens every time

  11. the Queen wins.

  12. player 1..hope that helps

  13. player 1 because 3 queens beat 3 tens the only reason the high card matters is if its a tie  

  14. player one, it does not matter what your "high" card is with a 3 of a kind, 3 queens beats 3 tens period.

  15. QQQ

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