Pre-Algebra Question, Solve for z?

Question

b-az=c

The sad part is I'm in college, 3rd year in Calculus, but some how I manage to forget the basics...

I got z=b-c/a

....Is it right??? :/

Answer 1

-az = c - b

z = (c - b)/-a

or z = (b-c)/a

you need ()

Answer 2

correct!

Answer 3

no...

b-az=c

-az=c-b

   z=c-b/-a

I think...

Answer 4

I got z= -(c-b)/a    or z= (-c+b)/a

Answer 5

b - az = c

- az = c - b

- z = ( c - b ) / a

z = - ( c - b ) / a

= ( - c + b ) / a

= ( b - c ) / a

Yes, it is right.  The people that said that it was wrong didn't know that their answer is the same as yours.

Answer 6

yes it is

Answer 7

nope...c-b/-a