Question:

Pre Cal Help. 10 pts. best answer?

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What is the value of:

sin x

cos x

cot x

csc x

when:

tan x = 5/12

sec x = -13/12

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2 ANSWERS


  1. sin x=5/13

    cos x=-12/13

    cot x=12/5

    csc x=13/5


  2. sinx=sqrt{1-(cosx)^2} = sqrt{1- 1/(secx)^2}

    cosx = 1/sec x

    cot x = 1/tan x

    cosec x = 1/sin x

    or cosecx =sqrt{1+(cotx)^2}=sqrt{1 + (1/tan x)^2}

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