Question:

Precalc....?

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(sec^2 x-1)/(sinx) = (sinx)/(1-sin^2 x)

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  1. (sec^2X-1/(sinX)

    (tan^2X)/(sinX) (identity)

    (sin^2X/cos^2X)/(sinX) ( complex division and identity)

    (sinX)/(cos^2X)  ( look to your Pythagorean theory )

    = (sinX)/(1-sin^2X)

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