Preparation of 1 kg of ferrous sulphate?

Question

If I were to produce 1 kg of ferrous sulphate through reaction of sulphuric acid and iron, in what quantities would two of those chemicals be needed

Answer 1

The reaction would be

Fe + H2SO4 -----> FeSO4 + H2

1 kg of FeSO4 would be equal to

1 kg x 1000g/kg / 151.909 grams/mol = 6.58 moles of FeSO4

Since the reaction requires an equal amount of Fe and H2SO4

then you need

6.58 moles Fe x 55.845 g/mol = 367.46 grams

6.58 moles H2SO4 x 98.0836 g/mol = 645.39 grams