Question:

Probability of getting all four aces? no aces? at least one ace?

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Five cards are dealt from a standard deck. What's the probability of getting:

all four aces?

no aces?

at least one ace?

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  1. all four:

    48 / (52 * 51 * 50 * 49 * 48) * 5! = 0.0018%

    no aces:

    48/52 * 47/51 * 46/50 * 45/49 * 44/48 = 66%

    at least one: 1-66% = 34%

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