Probability question....?

Question

There is a lottery and 7 numbers are selected out of 33. Numbers between 1 and 33. I can pick 7 numbers, what are the odd's that I hit all 7 correct?

What are the odds to hit 6,5,4,3,2 correct?

thanks alot.

Answer 1

well theres a trick to the probability,  what lottery is it.  if its like the powerball than you would have a one of a billion of a chance to get it.  but if its like a small one parsay the gopher five.  you have like a 1 of a thousand of a chance.

Answer 2

i think its

1,868,030,564 back of tickets may have it or check the lotteries website

Answer 3

The answer above mine is detailed, but forgot to include the key aspect that you have 7 choices for the first number, 6 choices for the second, 5 for the third and so on.

Therefore you have to divide 21,531,121,920 by 7! (5040)

The odds that you hit all 7 correct are 1 / 4,272,048

which is much more reasonable.

Answer 4

Probability questions are the same regardless of the lottery. Simple probability in this case is subtractive multiplication.

What I mean is, for any single number, in this instance, the odds are 1 in 33. However, each subsequent number is reduced by 1, so the second number is 1 in 32, third is 1 in 31, etc. This is because as each number is selected, it is taken out of the running to be drawn again.

The second factor is multiplying all of these odds together. This looks like this

1         1         1                     1

--   x    --   x    --    etc until    --

33      32       31                   27

So, it's 33 x 32 x 31 x 30 x 29 x 28 x 27 = 21,531,121,920

So the odds in this scenario would be 21.5 BILLION to 1 that you will select all 7 correct.  Odds are cumulative depending on how many tickets you buy, so if you bought 10 tickets, it would drop to 2.15 Billion to 1 -- still very improbable.  If you bought 100 tickets that's 215 million to one. At 1,000 tickets, it's 21.5 million to one.

Many lotteries, like California's Mega, have a "Bonus" number which can be any of the however many numbers are available and is not subtractive. So if it was 7 plus the Mega number, you would multiply 21.5 billion by 33 again, which is roughly 710 billion to one.

Answer 5

There is a handy odds calculator at http://www.betstarter.com/lottery/LottoO...

Just enter 7 and 33 in the two boxes and the following results will be displayed:

7-of-7 = 1 : 4,272,048.0

6-of-7 = 1 : 23,472.8

5-of-7 = 1 : 625.9

4-of-7 = 1 : 46.9

3-of-7 = 1 : 8.2

2-of-7 = 1 : 3.1

1-of-7 = 1 : 2.7