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Probability that a random select student will have a GPA of less than 3.40 when mean is 2.75 and s = .45?

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Probability that a random select student will have a GPA of less than 3.40 when mean is 2.75 and s = .45?

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  1. For any normal random variable X with mean μ and standard deviation  ÃÂƒ , X ~ Normal( μ ,  ÃÂƒ ), (note that in most textbooks and literature the notation is with the variance, i.e., X ~ Normal( μ ,  ÃÂƒÃ‚² ).  Most software denotes the normal with just the standard deviation.)

    You can translate into standard normal units by:

    Z = ( X - μ ) /  ÃÂƒ

    Moving from the standard normal back to the original distribuiton using:

    X = μ + Z * σ

    Where Z ~ Normal( μ  = 0,  ÃÂƒ  = 1).  You can then use the standard normal cdf tables to get probabilities.

    If you are looking at the mean of a sample, then remember that for any sample with a large enough sample size the mean will be normally distributed.  This is called the Central Limit Theorem.

    If a sample of size is is drawn from a population with mean μ and standard deviation σ then the sample average xBar is normally distributed

    with mean μ and standard deviation  ÃÂƒ /√(n)

    An applet for finding the values

    http://www-stat.stanford.edu/~naras/jsm/...

    calculator

    http://stattrek.com/Tables/normal.aspx

    how to read the tables

    http://rlbroderson.tripod.com/statistics...

    In this question we have

    X ~ Normal( μx = 2.75 , σx² = 0.2025 )

    X ~ Normal( μx = 2.75 , σx = 0.45 )

    Find P( X < 3.4 )

    P( ( X - μ ) / σ < ( 3.4 - 2.75 ) / 0.45 )

    = P( Z < 1.444444 )

    = 0.925693

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