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The sum of the angles of any triangle is 180o. What are the three angles of a triangle if the sum of the first two angles is equal to the third angle and the difference of the first two angles is two-thirds of the third angle?

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  1. a + b = c

    a - b = 2/3c

    ----------------

    2a = 5/3c

    a = 5/6c

    -a -b = -c

    a - b = 2/3c

    -----------------

    2b = 1/3c

    b = 1/6c

    a + b + c = 180

    5/6c + 1/6c + c = 180

    2c = 180

    c = 90

    a = 5/6c = 5/6(90) = 75

    b = 1/6c = 1/6(90) = 15


  2. Let A, B, and C be the three angles. Then you have

    A + B + C = 180

    A + B = C

    A - B = (2/3)C

    Now, because A + B = C, you can substitute this into the first equation. Like this:

    (A + B) + C = 180

    (C) + C = 180

    2C = 180

    C = 90

    Using the second two equations you have

    A + B = 90

    A - B = 60

    Adding these two equations you have

    2A = 150

    A = 75

    Using the first equation (or any other) , you have

    A + B + C = 180

    75 + B + 90 = 180

    B = 180 - 90 - 75 = 15

    So

    A = 75, B=15, and C = 90

  3. a = the first angle

    b = the second angle

    c = the third angle

    a + b + c = 180° (solve by using substitution)

    a + b = c

    a - b = 2/3(c)

    a - b = 2/3(c)

    a - b = 2c/3

    3(a - b) = 2c

    2c = 3a - 3b

    c = (3a - 3b)/2

    a + b + c = 180°

    a + b + (3a - 3b)/2 = 180°

    2[a + b + (3a - 3b)/2] = 2[180°]

    2a + 2b + 3a - 3b = 360°

    2a + 3a + 2b - 3b = 360°

    5a - b = 360°

    a + b = c

    a + b = (3a - 3b)/2

    2[a + b] = 2(3a - 3b)/2

    2a + 2b = 3a - 3b

    2a - 3a + 2b + 3b = 0

    -a + 5b = 0

    a = 5b

    5a - b = 360°

    5(5b) - b = 360°

    25b - b = 360°

    24b = 360°

    b = 360°/24

    b = 15°

    5a - b = 360°

    5a - 15° = 360°

    5a = 360° + 15°

    5a = 375°

    a = 375°/5

    a = 75°

    a + b + c = 180°

    75° + 15° + c = 180°

    c = 180° - 90°

    c = 90°

    ∴ a = 75° , b = 15° , c = 90°

  4. a + b + c = 180

    a + b = c, 2c = 180 so c = 90

    a - b = 60 and we know that a + b = 90

    Add these two equations to get a = 75 and b = 15

  5. let's say:

    1st angle = x, 2nd angle = y, 3rd angle = z

    x + y + z = 180

    x + y = z

    x - y = 2/3 z

    =>

    x + y + z = 180

    x + y - z = 0

    x - y - 2/3 z = 0

    add the first 2 equations term by term:

    x + y + z + x + y - z = 180 + 0 =>

    2(x + y) = 180 => x + y = 90

    having this and the first equation:

    x + y + z = 180 =? 90 + z = 180 => z = 90

    replace this value in the 3rd equation:

    x - y = 2/3 * 90 => x - y = 60

    take now this result and the one found above:

    x + y = 90

    x - y = 60

    as before, sum the equations:

    x + y + x - y = 90 + 60 =>

    2x = 150 => x = 75

    you have x + y = 90 => 75 + y = 90 => y = 90 - 75 => y = 15

    so the 3 angles are:

    x = 75

    y = 15

    z = 90

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